Question

The population of a town increases every year by 2% of the population at the beginning of
that year. The number of years by which the total increase of population be 40% is​

Answer 1

Step-by-step explanation:

The population of a town increases every year by 2% of the population at the beginning of

that year. The number of years by which the total increase of population be 40% is

Answer 2

Step-by-step explanation:

lets assume that the initial population was P

lets assume that the initial population was Pnow after a year population will be

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02P

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xP

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xPSo after n number of years population will be

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xPSo after n number of years population will be=P x (1.02^n)

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xPSo after n number of years population will be=P x (1.02^n)now this population should be equal to P

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xPSo after n number of years population will be=P x (1.02^n)now this population should be equal to P+40%P, so

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xPSo after n number of years population will be=P x (1.02^n)now this population should be equal to P+40%P, so1.4P=P x (1.02^n)

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xPSo after n number of years population will be=P x (1.02^n)now this population should be equal to P+40%P, so1.4P=P x (1.02^n)1.4=1.02^n

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xPSo after n number of years population will be=P x (1.02^n)now this population should be equal to P+40%P, so1.4P=P x (1.02^n)1.4=1.02^n1.02117=1.02^n so n=17

lets assume that the initial population was Pnow after a year population will be= P+(2/100)P=P(102/100)=1.02PSimilarly after 2 years population will be =1.02x1.02xPSo after n number of years population will be=P x (1.02^n)now this population should be equal to P+40%P, so1.4P=P x (1.02^n)1.4=1.02^n1.02117=1.02^n so n=17that means after 17 years the total increase in the population will be 40% of that of initial population.

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