Question

The population of a town increasing 8th annual rate of 8% if present population of a town is 17496 then find the population of town before 2 year

Answer 1

x: population 2 years ago(principle)  y: population 2 years later(amount)

rate of  increment :8%   (r)   n=2 years (time)

y=x(1+r/100)∧n

17496=x(108/100)^2

17496=x (27/25)^2

17496* 625/729=x

x=15000 (population 2 years ago)

Please mark BRAINLIEST.