Question

The population of a town is 1,00,000 and
its annual increase is 10%, then the
correct population at the end of 3 years
is
(a) 1,33,000
(b) 1,33,111-
(c) 1,33,100
(d) 1,44,400​

Answer 1

Answer:

$\boxed{\begin{array}{|c|c|c|c|}  {1-4}\Large\sf {Ionic\:Compounds} & \sf \Large {Chemical\:Formula} & \Large \sf{Melting\:point_{(k)}} & \Large\sf {Boiling\:point_{(k)}}\\ &&& \\  {1-4} \sf Sodium\:Chloride & \sf NaCl & 1074 & 1686 \\ &&& \\ {1-4} \sf Lithium\:Chloride & \sf \sf LiCl & 887 & 1600 \\ &&& \\ {1-4} \sf Calcium\:Chloride & \sf CaCl_2 & 1045 & 1900 \\ &&& \\ {1-4} \sf Calcium\:Oxide & \sf CaO & 2850 & 3120 \\ &&& \\ \ {1-4} \sf Magnesium\:Chloride & \sf MgCl_2 & 981 & 1685 \\ &&& \\ {1-4} \end{array}}$

Answer 2

Answer:

10% of 100000 is 10000

so we multiply it with 3 year

so number of increase in 3 year = 30000

so population after 3 year = 130000