the population of a town is 121000. if it increases at the rate of 10% per annum, what is the difference between the population 3 years hence and that of 2 years ago
Answers
Given : population of a town is 121000
it increases at the rate of 10% per annum,
To Find : what is the difference between the population 3 years hence and that of 2 years ago?
Solution:
Let say population 2 years ago = P
Rate of increase = 10 %
Hence current population after 2 years
=> 121000 = P ( 1 + 10/100)²
=> 121000 = P ( 1.1)²
=> 121000 = 1.21P
=> P = 100000
population 2 years ago = 100000
population after 3 years = 121000 ( 1.1)³
= 161051
difference between the population 3 years hence and that of 2 years ago
= 161051 - 100000
= 61051
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Answer:
61051 this is the difference