Question

The population of a town is 80000. If the population
increases at the rate of 75per 1000, find the population
of this town after 2 years.​

Answer 1

Step-by-step explanation:

population increased after two years =

\frac{80000}{1000 } \times 75 \times 2 = 12000100080000×75×2=12000

therefore, the population after 2 years = 80000+12000=92000

Answer 2

$\large{\colorbox{cyan}{✓Verified answer}}$

Principal= ₹12000

Rate= 10p.c.p.a(Percent Per Annum)

No. of years= 3 years

$\small\red{\underline{Simple \: Interest}} \tiny=\frac{Principal×Rate×Interest}{100} \\ \tiny = \frac{12000\times 10 \times 3}{100} \\ \tiny= \frac{120 \times 10 \times 3}{1} \\ \tiny = 1200$

Hence, 1,200 is the population of this town.