Question

The population of a town is 85184 and its annual increase is 10% then the population of the town three years ago was-

I will make him/her brainlist who will answer this question.....
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Answer 1

Let population of town three years ago be x.

population after three years

=x(1+10/100)³

=x (1+1/10)³

=x (11/10)³

=1331x/1000

according to question

1331x/1000=85184

x=85184×1000/1331

x=64000

Answer 2

Given : The population of a town is 85184 and its annual increase is 10%

To find : The population of the two three years ago.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the population of 3 years ago)

Here, we have to use the following mathematical formula.

Present population = Past population × [1 + (Rate of increase per annum/100)]ⁿ

Here, n = number of years for which the population has been increased.

(This formula has been generated from the formula of compound interest, where the principal amount is compounded annually.)

Let, the population of 3 years ago = x

By, putting the available data in the above mentioned mathematical formula, we get :

85184 = x × [1+ (10/100)]³

85184 = x × (11/10)³

85184 = x × (1331/1000)

x = 85184 × (1000/1331)

x = 64000

3 years ago, the population was = x = 64000

(This will be considered as the final result.)

Hence, 3 years ago, the population was 64000