Question

The population of a town is now 92610.
of the population growth rate is 5% P.a. then
what was the population of town 3 yrs. ago.
The rate of depreciation of a car in sopa​

Answer 1

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Hey Mate!!

Given,

Rate of depreciation = 5% p.a.

Current population = 92610

First Year

We know that the rate of depreciation is 5% p.a.. So, the population every year will be 105% if its next year's population. (Since, (100 + 5) = 105%.)

Thus, the population 1 year ago:

⇒ 105% of 92610

⇒ $\frac{105}{100} \times 92610$

⇒ $\frac{21}{20} \times 92610$

⇒ $\frac{21}{2} \times 9261$

⇒ 10.5 × 9261

⇒ 97,240.5 = 97,240 (approx.)

Second Year

⇒ 105% of 97240

⇒ $\frac{105}{100} \times 97240$

⇒ $\frac{21}{20} \times 97240$

⇒ $\frac{21}{2} \times 9724$

⇒ 21 × 4862

⇒ 102,102

Third Year

⇒ 105% of 102102

⇒ $\frac{105}{100} \times 102102$

⇒ $\frac{21}{20} \times 102102$

⇒ $\frac{21}{10} \times 51051$

⇒ 2.1 × 51051

⇒ 107,207.1 = 107,201 (approx.)

Thus, the population three years ago was 107,201.