Question

The population of a town was 3600 three years back and is now 4800. What will be the
population three years down the line if the rate of growth is constant and is
compounded annually?
1.5200
2. 7200
3. 5000
4. 6400-√
kindly explain​

Answer 1

Answer:

4. 6400

Step-by-step explanation:

Population 3 years ago- 3600

Current population- 4800

Population after 3 years- p

Growth rate- x

Growth rate is constant so it is going to be same next 3 years, so:

3600*x^3=4800

4800*x^3=p

Then:

4800/3600=p/4800

p=4800*4/3=6400

Answer 2

Step-by-step explanation:

Given: population of town 3 years back is $3600$, and in present is $4800$

To find: The population after 3 years or 'p'

For calculation of population,

We know that population 3 years ago was $3600$

The current population is $4800$

We assume that population after 3 years is 'p' and the growth rate is 'x'

Since the growth rate is constant,

⇒ $3600$ × $x^{3} = 4800$ and,

⇒ $4800$ × $x^{3} = p$

Thus,

⇒ $\frac{4800}{3600} = \frac{p}{4800}$

⇒ $\frac{4}{3}$ × $4800 = p$

⇒ $p = 6400$

The population three years down the line if the rate of growth is constant and is compounded annually is 4. 6400.