the population of a town was 62500 on the last day of the year 2001.During the next two years, it increased by 4% but in the year 2004,there was a decrease in the population by 10% due to an epidemic. Find its population at the end of the year 2004.
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Answer is 30879.
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A=p(1+r/100)²(1-r/100)=62500(1+4/100)²(1-10/100)=62500(1+1/25)²(1-1/10)=62500(26/25)²(9/10)=62500×(676/625)(9/10)=100×676×9/10=10×676×9=60840hence at the end of 2004 population will be 60840666
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