The population of a village decreases at the rate of 8% per annum. If its population 3 years ago was 64000000, what is it's approximate present population?
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4,98,36,032 is the answer to this qn
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Answer: 4,98,36,032
Step-by-step explanation:
Population of a village 3 years ago was 64000000.
Population of the village decreased at the rate of 8% per annum.
According to the problem,
This is a case of uniform decrease.
According to the formula of Compound Interest, p(1-r/100)^n is used to calculate uniform decrease where p= principal,r= rate of increase or decrease, n=time taken.
So now applying the formula,
64000000*(1-8/100)^3
=64000000*(92/100)^3
=64000000* (92/100)*(92/100)*(92/100)
=64*92*92*92
=4,98,36,032
Therefore present population of the village is 4,98,36,032.
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