Question

The population of a village increases at the rate of 7%every year .if the present population is 90,000.what will be population after 2yrs

Answer 1

A = $p {(1 + \frac{r}{100} )}^{t}$

Now, Putting values,
$= 90000 {(1 + \frac{7}{100} )}^{2} \\ = 90000( { \frac{107}{100}) }^{2} \\ = 90000 \times \frac{107}{100} \times \frac{107}{100 } \\ = 9 \times {107}^{2} \\ = {3}^{2} \times {107}^{2} \\ = {(3 \times 107)}^{2} \\ = {321}^{2} \\ = 103041$

Population of city after 2 years will be 103041.

Thanks m8 for asking this Noob Question.

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