the population of a village increases by 10% every year its population at the end of 2015 was 7986 what was its population at the beginning of 2013
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let x be the population in 2013
principal/population-x
time-2 years
rate-10%
Amount/total population- p(1+r/100)^t
7986=x(1+10/100)^2
7986=x(11/10)^2
7986=121x/100
7986*100/121=x
6600=x
population in 2013 was 6600
principal/population-x
time-2 years
rate-10%
Amount/total population- p(1+r/100)^t
7986=x(1+10/100)^2
7986=x(11/10)^2
7986=121x/100
7986*100/121=x
6600=x
population in 2013 was 6600
Tarun1211:
nice explaination
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