Question

the population of a village two years ago , was 625. it decreased every year at the rate of 4% per annum . it's present population is.​

Answer 1

Step-by-step explanation:

The given problem is a exponential decay problem.

The exponential decay function is given by :-

y=A(1-r)^xy=A(1−r)

x

, where A is the initial amount , r is the rate of change in decimal and x is the time period.

Here, the initial population = 62500

Time period x =2

Rate of decay = 4%

Then the present population=y=62500(1-0.04)^2=62500(0.96)^2=57600y=62500(1−0.04)

2

=62500(0.96)

2

=57600

Hence, the present population= 57600

Answer 2

Answer:

625 x [1 - 4/100]^2

625 x 24/25 x 24/25

ANSWER IS: 576