the population of a village was 30,000 in 2011.Every year,the population of the village increases by 1/10 of its previous year.What is the population of the year after 2 years
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1
Hi, Trishavasoya here is your solution
The population of a village was 30,000 in 2011
Every year,the population of the village increases by 1/10
∴ after 2 years total population will be =[1+1/10]^2 *population at first
⇒after 2 years total population will be =[1+1/10]^2 *30,000
⇒[11/10*11/10*30,000]= 121*300 =36300
after 2 years total population will be 36300 ANS
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Answered by
0
population = 30,000 in 2011
population increases by 1/10 annually
∴ after 1st years population =[1+1/10] *30000 =33000
∴after 2nd years population =[1+1/10] *33000 =36300
⇒after 2nd years total population will be =36300 ans
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