Math, asked by trishavasoya1234, 1 year ago

the population of a village was 30,000 in 2011.Every year,the population of the village increases by 1/10 of its previous year.What is the population of the year after 2 years

Answers

Answered by debtwenty12pe7hvl
1

Hi,  Trishavasoya here is your solution

The population of a village was 30,000 in 2011

Every year,the population of the village increases by 1/10

∴ after 2 years total population will be =[1+1/10]^2 *population at first

⇒after 2 years total population will be =[1+1/10]^2 *30,000

⇒[11/10*11/10*30,000]= 121*300 =36300

after 2 years total population will be 36300 ANS

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Answered by joytwenty12
0

population = 30,000 in 2011

population increases by 1/10 annually

∴ after 1st  years  population  =[1+1/10] *30000 =33000

∴after 2nd  years  population  =[1+1/10] *33000 =36300

⇒after  2nd years total population will be  =36300 ans



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