The population of Andhra Pradesh was 5.4*10^7 in 1988. If a population was growing at a constant rate of 2.4percent per annum . What was the population in 2008A.D. [given that (1.024)^20=1.60694]
Answers
Answered by
243
The population in a particular year can be given by
Pn = Po(1 + r/100)^n
Where Po= population in 1988
Pn = population in n years after 1988
r = population growth rate
n= no. of years after 1988
in this case
Pn = 4,5x10^7
n = 20
r= 2.4%
So, P2008 = 5.4x10^7(1+2.4/100)^20
= 5.4x10^7 x 1.60694
= 8.677 x 10^7
Pn = Po(1 + r/100)^n
Where Po= population in 1988
Pn = population in n years after 1988
r = population growth rate
n= no. of years after 1988
in this case
Pn = 4,5x10^7
n = 20
r= 2.4%
So, P2008 = 5.4x10^7(1+2.4/100)^20
= 5.4x10^7 x 1.60694
= 8.677 x 10^7
Answered by
12
Step-by-step explanation:
po the population in a particular year can be given by
population equals population (1+r/100)*n
population in 1988
population in n years after 1988
r = population growth rate
n = number of years after 1988
p = 5.4*10 raise to the power 7
n = 20
r = 2.4 %
2008 = 5.4 into 10 raise to the power 7 ( 1+2.4/100)*20
= 5.4*10 raise to the power 7 multiply by 1.60694
answer = 8.677 into 10 raise to the power 7
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