Question

The population of Andhra Pradesh was 5.4*10^7 in 1988. If a population was growing at a constant rate of 2.4percent per annum . What was the population in 2008A.D. [given that (1.024)^20=1.60694]

Answer 1

The population in a particular year can be given by

Pn = Po(1 + r/100)^n
Where Po= population in 1988
Pn = population in n years after 1988
r = population growth rate
n= no. of years after 1988

in this case
 Pn = 4,5x10^7
n = 20
r= 2.4%
So, P2008 = 5.4x10^7(1+2.4/100)^20
                  = 5.4x10^7 x 1.60694
                  = 8.677 x 10^7

Answer 2

Step-by-step explanation:

po the population in a particular year can be given by

population equals population (1+r/100)*n

population in 1988

population in n years after 1988

r = population growth rate

n = number of years after 1988

p = 5.4*10 raise to the power 7

n = 20

r = 2.4 %

2008 = 5.4 into 10 raise to the power 7 ( 1+2.4/100)*20

= 5.4*10 raise to the power 7 multiply by 1.60694

answer = 8.677 into 10 raise to the power 7