Question

the population of city increase by 10 percent in one year and decrease by 10 percent next year if at the end of second year the population is 99000 what was the it at the beginning of 1st year​

Answer 1

Answer:

ofcourse 99000 //////////

Answer 2

Answer:

100000

Step-by-step explanation:

let the population of city= x

10% of x= (10/100)x= (1/10)x

so increase in population after 1 year = x+ (1/10)x=(11/10)x

Now 10% of (11/10)x= (10/100)*(11/10)x=(11/100)x

so population after 2 years=(11/10)x-(11/100)x=(99/100)x

Again, (99/100)x=99000

so, x=99000*(100/99)= 100000