Question

the population of the city was 10000 in 1991 .it is increased by 5℅ every year what is population in 1994​

Answer 1

Answer:

12000

Step-by-step explanation:

Let the population in 2006 be x.

Pop. in 2009=x×(1+

100

5

)

3

⇒1,38,915=x×(

20

21

)

3

⇒x=

9261

138915×8000

=120000

Answer 2

$\huge\boxed{\fcolorbox{pink}{black}{\pink{Answer}}}$

Given$\longrightarrow$

Population in 1991=10000

Population increase every year =5%

To Find$\longrightarrow$

Population in 1994

Solution$\longrightarrow$

Population in 1992=

$\frac{5}{100} \times 10000$

$5 \times 100 = 500$

Population in 1992=10000+500=10500

Population in 1993=

$\frac{5}{100} \times 10500$

$\frac{1}{20} \times 10500$

$525$

Population in 1993= 10500+525=11025

Population in 1994 =

$\frac{5}{100} \times 11025$

$\frac{1}{20} \times 11025$

$551.25$

Population in 1994= 11025+551.25=11576.25

Population in 1994 is 11576 (approx) .