the population of town increases 10% annually if the present population is 204600 what was it an year ago?
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Answered by
11
Let population one year ago be x.
increase it by 10% which results in 204600
x+10%x = 204600
x(1.1) = 204600
x = 204600÷1.1
x = 186000
population one year ago = 186000
increase it by 10% which results in 204600
x+10%x = 204600
x(1.1) = 204600
x = 204600÷1.1
x = 186000
population one year ago = 186000
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Answered by
5
Let one year ago population be X
10%of X =X×10/100
=X/10
X+X/10=204600
11X=2046000
X=2046000/11
X=186000
hence population of one year ago is 186000.........
10%of X =X×10/100
=X/10
X+X/10=204600
11X=2046000
X=2046000/11
X=186000
hence population of one year ago is 186000.........
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