Question

The population Or a town is increasing at the rate of 4% per annum. If two years ago, the population of the town was 70,000, find its present population. ​

Answer 1

Answer =

Population before 2 years = 70,000

Rate of increasing population = 4%

$\frac{4}{100} \times 700000 \\ 2800$

hence, population increasing per year is 2800

To find: Present Population

Present population of town =70,000+(2800×2)

= 70000+(5600)

= 75600

Hence, present population of town is 75600

Answer 2

Answer:

To find the present population of the town, we can use the information given.

Let's denote the present population as P.

According to the given information, the population is increasing at a rate of 4% per annum. This means that every year, the population increases by 4% of its current value.

Two years ago, the population was 70,000. So, we can calculate the population after one year from two years ago as follows:

Population after one year = 70,000 + (4/100) * 70,000

Simplifying this equation gives:

Population after one year = 70,000 + 0.04 * 70,000

= 70,000 + 2,800

= 72,800

Now, we can calculate the present population by adding one more year to the population after one year:

Present population = Population after one year + (4/100) * Population after one year

Substituting the value of the population after one year, we get:

Present population = 72,800 + 0.04 * 72,800

= 72,800 + 2,912

= 75,712

Therefore, the present population of the town is 75,712.