The populations and land areas of four cities in Texas are shown.
Answers
Answered by
0
Answer:
The population density for city b would be 48,592 ÷ 26
The population density for city b is more than the city c
And, the city d contains the lowest population density
Step-by-step explanation:
The computation is given below:
As we know that
Population density = Population ÷ Area
So
For city A = 2,195,914 ÷ 1,553 = 1413.98
For city B = 48,592 ÷ 26 = 1868.15
For city C = 1,257,676 ÷ 999 = 1258.93.
For city D = 196,429 ÷ 258 = 761.35.
The following are the true statements:
The population density for city b would be 48,592 ÷ 26
The population density for city b is more than the city c
And, the city d contains the lowest population density.
follow
Answered by
0
- Houston _____ 2,304,580
- San Antonio____1,434,625
- Dallas______ 1,304,379
- Austin ______961,855
Thank you.Hope it will help
Similar questions