Math, asked by aditiagarwal1755, 15 hours ago

The populations and land areas of four cities in Texas are shown.

Answers

Answered by sreenithibanerjee
0

Answer:

The population density for city b would be 48,592 ÷ 26

The population density for city b is more than the city c

And, the city d contains the lowest population density

Step-by-step explanation:

The computation is given below:

As we know that

Population density = Population ÷ Area

So

For city A = 2,195,914 ÷ 1,553 = 1413.98

For city B = 48,592 ÷ 26 = 1868.15

For city C = 1,257,676 ÷ 999 = 1258.93.

For city D = 196,429 ÷ 258 = 761.35.

The following are the true statements:

The population density for city b would be 48,592 ÷ 26

The population density for city b is more than the city c

And, the city d contains the lowest population density.

follow

Answered by SundusWani
0
  1. Houston _____ 2,304,580
  2. San Antonio____1,434,625
  3. Dallas______ 1,304,379
  4. Austin ______961,855

Thank you.Hope it will help

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