Question

The position coordinates of an object are given by x =2t^2, y=t^2-4t. The average velocity of particle in 1st one second is

Answer 1

X =(t-2)^2 = t^2–4t + 4

v = 2t - 4

Distance covered = integ(|v|dt)

= |t^2–4t|

= 4t - t^2 for t = 0 to 2

= t^2 - 4t for t = 2 to 4

= 8 units

Answer 2

Answer:

The answer is 5units

Explanation:

hope it's help