Question

The position cordinate of a moving particle is given by x=6+18t+9t2, where x is in meters and t is in seconds what is its velocity at t=2sec

Answer 1

Position coordinate is 6+18t+9t²

if we differentiate it with time we get velocity that is 18+18t

putting t=2, we get velocity at two seconds that is 54m/s

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Answer 2

velocity is slope of distance curve or line in distance - time graph
so v = dx/dt = 0 + 18 + 18t
= 18 + 18t

so at t = 2s
v = 18+18×2
= 18+36
= 54