Question

The position of a body can be represented AS x= 6t² +8t +12 The acceleration of The body at t=2 sec​

Answer 1

Answer:

a=

dt

2

d

2

x

=

dt

2

d

2

(2t

3

−6t

2

+12t+6)=0

⇒12t−12=0

[t=1sec]

Answer 2

Answer:

Acceleration =12m/s2

Explanation:

The position of the body can be represented as x=$6t^{2} +8t+12$

Acceleration =velocity/time

                    =dv/dt

Velocity =  distance/time

             =ds/dt

∴ Velocity =$d/dt(6t^{2} +8t+12)$

                 =12t+8

∴ Acceleration = $d/dt(12t+8)$

                        =12m/s2

     Acceleration is 12m/$s^{2}$

#SPJ2