The position of a body moving along x axis at time t is given by x=(t^2-4t+6) m . The distance travelled by body in time interval t=0 to t=3 sec is ?
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give the equation
x=t²-4t+6
and interval Time intial time t=0 and final time t¹=3sec we find out that d=?
dx/dt=d/dt(t²-4t+6)
=2t-4+0
=)d=2×3-4=2m
therefore the body moving distance =2m
x=t²-4t+6
and interval Time intial time t=0 and final time t¹=3sec we find out that d=?
dx/dt=d/dt(t²-4t+6)
=2t-4+0
=)d=2×3-4=2m
therefore the body moving distance =2m
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