English, asked by kaajuu3065, 1 year ago

The position of a partical moving on a straight line path is given by: x=12+18t+9t2 meter its acceleration at t=55s is

Answers

Answered by tommy01

0

dx/dt = v = 18+ 18t
dv/dt = a = 18m/s^2 . thus a is 18m/s^2 at 55s

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