Physics, asked by arushi150203, 1 year ago

The position of a particle along x-axis at time t is given by x=1+t-t^2, the distance travelled in first 2 second is ?

Answers

Answered by hakzhari
0

x = 1 + t - t^2

x at t=2 sec.

x = 1 + 2 - 2^2

x = 3 - 4

x= -1 m


This implies that the particle is at rest at t =2 sec


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