Question

the position of a particle going along a straight line is X1 is equal to 100 m at 10 a.m ,x 2 = 200 m at 10:30 p.m the velocity of particle is​

Answer 1

Follow the given picture

Answer 2

Explanation:-

$\boxed{\sf\;\underline{Velocity=\frac{x_f-x_i}{t_1-t_1}}}$

$\sf\;x_f=200\;m\\\\x_i=100\;m\\\\t_1=10:30\;am\\\\t_2=10:00\;pm$

So let's put the data in the formula to get velocity:-

$\sf\;Velocity=\frac{x_f-x_i}{t_1-t_1}\\\\Velocity=\frac{200-100}{10:00\;am-10:30\;pm}\\\\Velocity=\frac{100}{12\;hours\;30\:min}\\\\12\;hours\;30\;min=750\;min\\\\Velocity=\frac{100}{750}\\\\Velocity=0.1333\;m/min$

So the velocity of particle is 0.1333 m/min