Question

the position of a particle is a function of time,given x=(t^3-t^2+4)m(where t in secs ).When the acceleration of particle is zero then its velocity will be

Answer 1

By , the differentiation of position with respect to time i.e v= dx/dt d/dt(t^3-t^2+4). we get. 3t^2-2t now again differentiating this value. we get 6t - 2 which is equal to 0. we get t = 1/3 putting value of t. we get. v = 1m/s