The position of a particle is given as x=5t³.
Find the accelaration of the body at t=2sec
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0
Answer:
accelaration of the body at t=2sec is 60m/s²
Answered by
1
Answer:
60 m/s²
Explanation:
acceleration=dx/dt (differentiation)
x=5t³
dx/dt = d(5t³)/dt
on differentiation
(d/dx of x^n = xn^(n-1)--> formula for differentiation)
dx/dt= 15t²
now this dx/dt will give you acceleration by putting the value of t.
since t= 2 sec
a = 15×(2²) = 15× 4 = 60m/s²
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