The position of a particle is given by r = (3tî + 21²₁ + 4k)m, t is in sec speed of particle at t = 2 sec is :
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Given,
Position of the Particle r = (3tî + 21²₁ + 4k)m
where,t is in sec
To find,
Speed of particle at t = 2sec
Solution,
As we that Speed= Distance/Time
∴The speed of a particle(v)=dr/dt
=d(3tî + 21²₁ + 4k)/dt
=3î
so, speed at t=2sec
speed (v) =3îm/sec
So, speed of particle at t = 2sec is 3îm/sec
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