Physics, asked by Vishurj1334, 1 year ago

The position of a particle is given by r = 3ti – 2t2j +4k m where ‘t’ is in seconds and the coefficients have the proper units for r to be in metres.



Find ‘v’ and ‘a’ of the particle.

What is the magnitude and direction of velocity of the particle at t = 2 sec.?

Answers

Answered by ravisanthi1973
18

the positiby on of a particle is given r=(i+2j-k} an momentum p=3i+_4j-2k) the angular momentum is perpenticular to

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