Question

the position of a particle moving along a straight line is defined by the relation, x=t^3-6t^2-15t+40 where x is in meters and t is in seconds. the distance travelled by the particle from t=0 to t=2s is​

Answer 1

Explanation:

slope of xt graph give velocity

so v=3t²-12t-15

v=0 at t=5 and t=-1

so at t=0 x=40

t=2 x= -6

so distance traveled |-6-40|=46