the position of a particle moving along a stright line is given by x=4t-3t^2m find accelaration of the particle at t=2 seconds
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Given :-
The position of a particle moving along a straight line = x = 4t - 3t².
Time in which we are required to find the acceleration = 2 s
In this question we are required to double different the given value of x w.r.t to dt.
What is requirment of double differentiation?
We usually do double differentiation in this term to find acceleration. In a single differentiation we will find Velocity and again if we differentiate velocity w.r.t dt then we will get acceleration of the particle.
v = dx/dt
v = d(4t-3t²)/dt
v = 4-6t m/s ( dx/dt = nxⁿ-¹)
Again,
a = dv/dt
a = d(4-6t)/dt
a = -6 ms-² Answer.........
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