The position of a particle moving along the x-axis depends on the time as x = (3t2 - 2t3) where ''x'' is in metres and ''t'' is in seconds. Plot the velocity - time graph and thus find the distance and displacement of the particle in the interval t = 0 to t = 4seconds. plzzz replyy fast.
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velocity= dx/dt= d(3t2-2t3)/dt= 6t-6t2= 6t(1-t)
velocity is zero at t=0 and t=1
so the graph is the parabola which cuts the x axis at 0 and 1...
at t= 0.... x= 0
at t=4.....x=3(4)²-2(4)³= 48-128= -80 m
so distance= 80m and displacement= -80m
velocity is zero at t=0 and t=1
so the graph is the parabola which cuts the x axis at 0 and 1...
at t= 0.... x= 0
at t=4.....x=3(4)²-2(4)³= 48-128= -80 m
so distance= 80m and displacement= -80m
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