The position of a particle moving along x-
axis is given as : x = (-2t3 + 3t2 + 5)m. The
acceleration of the particle at the instant its
velocity becomes zero is :-
Answers
Answered by
6
Answer:
The position of a particle moving along x-axis is given by
x=(−2t
3
+3t
2
+5)m
Velocity, v=
dt
dx
=0
−6t
2
+6t=0. . . . . . .(1)
6t(−t+1)=0
−t+1=0
t=1sec
Acceleration, a=
dt
dv
a=−12t+6
a∣
t=1sec
=−12×1+6
a∣
t=1sec
=−6m/s
2
The correct option is C.
Explanation:
hopes it help u
Similar questions