The position of a particle moving along x axis varies with time as x = 10 - 2t^2 + 4t , where x is in metres and t is in seconds find the distance travelled by particle in first 4s.
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just put t = 4 in the given relationship..
x(t=2) = 10 -2(16) + 16
x = -6
x(t=2) = 10 -2(16) + 16
x = -6
aryansinghverma:
It is not right answer as distance cannot be in negative . the correct answer is 20 m
the relationship might not be correct
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