Question

The position of a particle moving along y axis is given as y =5t2-10t+2m the position of particle when is velocity is zero is

Answer 1

Answer: -3

Explanation:

Dy/dt=10t-10

10t=10

t=1s

Y=5-10+2

=-3m

Answer 2

The position of particle when is velocity is zero is 2m - 5

Given

The position of a particle moving along y axis is given as y =5t2-10t+2m

To Find

We need to find the  the position of particle when is velocity is zero.

Solution

We know

 y = 5$t^{2}$ - 10t + 2m

Velocity is the rate at which displacement changes with time.

V =  $\frac{dx}{dt}$

    = $\frac{d}{dt}$ ( 5$t^{2}$ - 10t + 2m)

    = 10t - 10

When velocity is zero

10t - 10 = 0

       10t = 10

           t = 1

At t=1 velocity become zero

So the position at that time will be

At t=1           ⇒  (5 × $1^{2}$ )- (10 ×1) + 2m

                   ⇒ 5 - 10 + 2m

                   ⇒ 2m - 5

y = 2m -5 at t= 1

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