Physics, asked by rock970, 1 year ago

The position of a particle moving on a straight line path is given by X = 4 tCube + 3tsquare metre its velocity at t = 23 seconds is

Answers

Answered by sadhanabrijendrakhar
0

Differentiate the given equation with respect to dt

dx/dt=4t^3/dt+3t^2/dt

V =12t^2+6t

Put t=23

It will give you the answer

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