The position of an object is given by the equation x = 3.0t2 + 1.5t + 4.5, where x is in meters, and t is in seconds. what is the instantaneous acceleration of the object at t=3.0s?
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so acceleration at t=3s is 6m/s2
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we know acceleration is rate of change of velocity
while velocity is rate of change of displacement
acceleration,a=d/dt(d/dt(s))
a=(d/dt(d/dt(3t2+1.5t+4.5)))
a=6
while velocity is rate of change of displacement
acceleration,a=d/dt(d/dt(s))
a=(d/dt(d/dt(3t2+1.5t+4.5)))
a=6
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