Question

the position of an object moving along x axis is given by x= 5 + 10t2. the average velocity between t= 2s and 4s is​

Answer 1

Answer:

Velocity is = 0 + 2bt = 2bt = 5t, after dt

putting b= 2.5 Velocity at t = 0 is v= 5 x 0 = 0

Velocity at t = 2sec is v = 5 x 2 = 10m/s xat t = 2sec is x = 8.5 +2.5(2)² = 18.5meter

x att = 4sec is x = 8.5 + 2.5(4)2 = 48.5meter

so the displacement between t = 2 and t = 4

is 48.5 - 18.5 = 30 meter

displacement

time

Vo) 46 LTE

so average velocity will be

30m (4-2)sec

15m/s

Explanation:

using the up anser u can