The position of an object varies with time t as X=at^2-bt^3 at what time will the acceleration of the object will become zero
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heya,
by double differentiating x wrt time we get
a=2a-6bt
2a-6bt=0
t=2a/6b
hope it helps!
by double differentiating x wrt time we get
a=2a-6bt
2a-6bt=0
t=2a/6b
hope it helps!
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