Question

the position of both an electron and a Helium atom is known within 1 nanometre further the momentum of the electron is within 5 ×10^-26 kg metre per second the minimum of uncertainty in the measurement of momentum of Helium atom is

Answer 1

The momentum of helium is equal to the momentum of electron .

Answer 2

Answer : The momentum of Helium atom is $5\times 10^{-26}Kg.m/s$.

Explanation : Given,

Position of both an electron and a Helium atom = 1 nm

The momentum of an electron = $5\times 10^{-26}Kg.m/s$

Uncertainity principle : It is defined as the position and the momentum both can not be determined simultaneously.

According to the Uncertainity principle,

$\Delta x\times \Delta p\geq \frac{h}{4\pi}$

where,

$\Delta x$ = position of an atom

$\Delta p$ = momentum of an atom

h = Planck's constant

When the position of an electron and helium atom is same and the momentum of an electron is known then the momentum of helium atom is equal to the momentum of an electron.

Therefore, the momentum of Helium atom is $5\times 10^{-26}Kg.m/s$.