The position of the body moving along x-axis at time t is given by x(t square_4t+6)m the distance traveled by body in time interval t= 0 to t=3s is
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Answered by
1
We're asked to find the distance traveled by the object after the first three seconds of its motion, given its one-dimensional position equation.
Notice that it doesn't ask for the displacement of the particle, it asks for the total distance traveled. With that in mind, we can't simply plug in the
t
=
0
and
t
=
3
s
values and have that be the answer, we would have to substitute all values for
t
:
Since it's asking for the distance traveled, we can disregard the "
+
6
" quantity in the equation, because at time
t
=
0
it obviously hasn't gone anywhere yet. The process a as follows:
x
(
0
)
=
(
0
)
2
−
4
(
0
)
=
0
m
x
(
0
)
=
(
1
)
2
−
4
(
1
)
=
−
3
m
x
(
2
)
=
(
2
)
2
−
4
(
2
)
=
−
4
m
x
(
3
)
=
(
3
)
2
−
4
(
3
)
=
−
3
m
We can see that the particle traveled
4
meters in the negative direction, and then one meter in the positive direction. The total distance it traveled was
4
m
+
1
m
=
5
m
anilchoubey25:
Why have we taken initial position as 6
Answered by
5
hope this may help u to solve
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