The position of the particle as a function of time x=6t+0.5t^3. what is the velocity at t=1s
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differentiate it with respect to time
velocity = 6 + 1.5t²
now velocity at 1 second = 6 + 1.5 = 7.5 m/s
velocity = 6 + 1.5t²
now velocity at 1 second = 6 + 1.5 = 7.5 m/s
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Answer:
7.5m/s. Hope it's helpful to you...
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