Question

The position of the particle is given by the relation:
S = 6t3-3t2-16t+65 where “S” is in meter and time‘t’ is in second. Determine, a) the time at which the velocity is zero b) acceleration of the particle at that time c) the distance travelled by the particle from t=4s to t=7s l​

Answer 1

Answer:

v=18t2-6t-16

a=36t-6

t=6 sec