Question

The position of the particle is represented by y = ut - ½ gt2
a) What is the force acting on the particle?
b) What is the momentum of the particle?

Answer 1

Explanation:

y=ut-1/2gt^2

dy/dt=V=u-gt

d^2 y/dt^2=a=-g

a)F=ma=m(-g)= -mg

b)P=mV=m(u-gt)