Find the distance and displacement covered by an object when it comes two and a half round of a circular path of radius 42 cm
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Answer:
one round=2πr =2×(22/7)×42
distance covered in two and half round=
(5/2)×2×(22/7)×42
=(5×2×22×42)/(2×7)=660
Displacement =(1/2)×2πr =(22/7)×42=132
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