Question

The position time graph of a particle of 2 kg moving along x axis is as shown in the figure. The magnitude of impulse on thr particle at t=2 s is

Answer 1

Answer:

Answer

Velocity is nothing but the slope of x−t graph, so the velocity just before t=4 will be

V

1

=slope=

(4−0)sec

(20−0)m

=5m/sec

the velocity just after t=4 will be

V

2

=slope=

(8−4)sec

(0−20)m

=−5m/sec

so the change in momentum at t=4sec will be ΔP=m(V

2

−V

1

)=1kg(−5−5)m/s=−10Kgm/s

if considering only magnitude the impulse is 10Kgm/s or 10N−sec