The position vector of a particle is determined by the
expression r = 3t^2î + 4t^2 j+ 7k. The displacement tra-
versed in first 10 seconds is:
(a) 100 m
(b) 150 m
(c) 300 m
(d) 500 m
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Answer:
r (i)= Initial position vector
r (f) = Final position vector
Since r is the finction of time.
r(i)=r(0)=7 k^
r(f)=r(10)=3*10² i^ + 4*(10)² j^ +7 k^
Now ,
Displacement vector= r(f)-r(i)
D= |300 i^ + 400j^ +(7-7)k^ |
=500
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