Question

The position vector of may object at nay time t is given by 3t^2i + 6tj+ k. It's velocity along y axis has the magnitude

Answer 1

x = 3t² i + 6t j + 1.k

differentiate with respect to time

dx/dt = 6t i + 6j + 0k

we know , dx/dt = velocity

so,

v = 6t i + 6 j + 0.k

hence , velocity along x -axis = 6t
velocity along y-axis = 6
and velocity along z-axis = 0


hence, velocity along y -axis = 6 unit

Answer 2

Hello sir ,

According to our question sir ,

The position vector of an object at time t is given by 3t^2i + 6tj+ k

Sir according to kinematics dx/dt = velocity! means rate of change of position with respect to time is known as velocity

Now for velocity we will differentiate the equation with respect to t

As velocity = d/dt ( 3t^2i + 6tj+ k )

We get velocity = > 6t i + 6 j +0

Our question is saying velocity along y axis so sir for better understanding

We will take it in our reference frame

Means velocity is given by (0.i + j + 0.k)(6t i + 6j+0k)

Which means velocity along y axis is 6 m/s sir

Hope this helps you !

# Regards brainly helper